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Question

The focal length of a diverging lens is negative. If f = −16 cm

 for a particular diverging lens, where will the image be formed of an object located 70 cm

 to the left of the lens on the optical axis?

Answer 1

1/f = 1/d + 1/x; -1/16 = 1/70 + 1/x; 1/x = -1/16 - 1/70 = - 86/(70·16) = -43/560; x = -560/43 = - 13 cm