equation and image

Question

The equation connecting s, p, and f for a simple lens can be employed for spherical mirrors, too. A concave mirror with a focal length of 7 cm

 forms an image of a small object placed 15 cm

 in front of the mirror. Where will this image be located? (For spherical mirrors, positive p means the image is on the same side of the mirror as the object.)

Answer 1

1÷p +1÷s=1÷f

p1​+1÷11​=31​

p=4.125\ cmp=4.125 cm

does not exist since the left hand limit does not equal the right hand limit.

a. lim x->0+ f(x)=0^2=0



b. lim x->0-f(x)=0



c. lim x-> 1 f(x)=1^2=1



d. lim x-> 2- f(x)=1^2=1 e. lim x-> 2+ f(x)=8-2=6



f. lim x-> 2 f(x) does not exist