Rebecca A.

asked • 04/05/23

Phy Review Question Part 2 Help

A potter's wheel, with rotational inertia 7.20 kg·m2 is spinning freely at 18.0 rpm. The potter drops a 2.70 kg lump of clay onto the wheel, where it sticks a distance of 50.0 cm from the rotation axis.


What is the subsequent angular speed of the wheel? (This I got correct to be 16.45 rpm)


What is the change in the rotational kinetic energy of the system? (Need help on this one)

Harris S.

tutor
Here are the things you need to take care of: 1: Find the moment of inertia of the total system, i.e., the wheel and lump 2: Once you have it, then use the law of conservation of angular momentum (Angular momentum = I*angular velocity) to find the angular velocity of the wheel after the lump is dropped 3: Once you have it, you can find the difference between two KE (with and without lump) 4: rotational KE = 1/2 * moment of inertia * angular _velocity 2
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04/05/23

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