Inactive Tutor answered 04/04/23
Tutor
New to Wyzant
x=5-5i
x-5=5i
x^2-10x+25=-25
x^2-10x+50=0
R=(x^2-10x+50)(x-1)^2
=(x^2-10x+50)(x^2-2x+1)
=x^4 -12x^3 +31x^2 -110x +50
Faith W.
asked 04/04/23R has degree 4 and zeros 5 − 5i and 1, with 1 a zero of multiplicity 2.
Inactive Tutor answered 04/04/23
x=5-5i
x-5=5i
x^2-10x+25=-25
x^2-10x+50=0
R=(x^2-10x+50)(x-1)^2
=(x^2-10x+50)(x^2-2x+1)
=x^4 -12x^3 +31x^2 -110x +50
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