We can use Stefan-Boltzmann law, which relates the radiated power of a blackbody to its temperature with the following equation
P = σ A ε T^4
where P is the power radiated,
σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4),
A is the surface area of the plate,
ε is its emissivity (which we assume to be 1 for a blackbody),
T: temperature in Kelvin.
First, we need to convert the dimensions of the plate to meters:
length = 0.14 m
width = 0.3 m
The surface area is:
A = length x width = 0.14 m x 0.3 m = 0.042 m^2
T = 1333 K
Now the power radiated:
P = σ A ε T^4 = (5.67 x 10^-8 W/m^2K^4) x (0.042 m^2) x (1) x (1333 K)^4 ≈ 1226.5 W
Hence, the metal plate will radiate approximately 1226.5 watts of power when heated to a temperature of 1333 K