Hi there!
Hope this helps!
a) anguler frequency = a_max/v_max = 15/3.5 = 4.29
b) spring constant = (angular_frequency)^2 * m = 4.29^2 * .05kg = 0.92
c) amplitude = v_max/(angular_frequency) = 0.82
Make sure to figure out the units!
Cheers!
Jeff
M1 L.
asked 03/27/23A mass of 50 g is attached to a spring and undergoes simple harmonic motion. ts maximum acceleration is
15 m/s^2 and its maximum speed is 3.5 m/s. Determine:
a) Angular frequency
b)Spring constant
c) Amplitude
Hi there!
Hope this helps!
a) anguler frequency = a_max/v_max = 15/3.5 = 4.29
b) spring constant = (angular_frequency)^2 * m = 4.29^2 * .05kg = 0.92
c) amplitude = v_max/(angular_frequency) = 0.82
Make sure to figure out the units!
Cheers!
Jeff
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.