Part A
5(sinθ+1) = 5
sinθ+1 = 1
sinθ = 0
θ = πn <-- This can be determined with the unit circle
Part B
7tanθ=2√3+tanθ
6tanθ=2√3
tanθ = √(3)/3
θ = π/6 + 2πn <-- This can also be determined with the unit circle
Hope the explanations helped!
Candy H.
asked 03/26/23solve for thea (show work)
A)5(sinthea+1)=5
B)7tanthea=2squrt3+tanthea
Part A
5(sinθ+1) = 5
sinθ+1 = 1
sinθ = 0
θ = πn <-- This can be determined with the unit circle
Part B
7tanθ=2√3+tanθ
6tanθ=2√3
tanθ = √(3)/3
θ = π/6 + 2πn <-- This can also be determined with the unit circle
Hope the explanations helped!
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.