
Yefim S. answered 03/26/23
Math Tutor with Experience
a) Let we have ΔBAC, b = 10.6, c = 4.0., B = 14°, b) By sine law: sin14°/10.6 = sinC/4; sinC = 4sin14°/10.6;
C = sin-1(4sin14°/10.6) = 5.238°; c) A = 180° - (14° + 5.238°) = 160.8°
There only 1 triangle, because C must be less then B