I read your problem as 6sin(θ)-1=2sin(θ)+1:
6sin(θ)-1=2sin(θ)+1
6sinθ=2sin(θ)+2
4sinθ=2
sinθ=1/2
θ = π/6+2πn, 5π/6+2πn <-- You can use the unit circle to get these values
Hope this helped!
Candy H.
asked 03/26/23Solve for Thea- 6sinthea-1=2sinthea+1
give the exact radian measure
no decimal
I read your problem as 6sin(θ)-1=2sin(θ)+1:
6sin(θ)-1=2sin(θ)+1
6sinθ=2sin(θ)+2
4sinθ=2
sinθ=1/2
θ = π/6+2πn, 5π/6+2πn <-- You can use the unit circle to get these values
Hope this helped!
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