Torque ----------

Question

Answer 1

If I knew the force shown in red in my sketch (we'll call it F_x), then the torque = rF_x (radius times force) where the radius is the length of the fishing pole.

To calculate the component of the force (F_x), consider that it makes a 90° angle with the pole, composed of the 20° angle, the 37° angle and, we'll call the rest, angle θ. So θ = 33° (33 + 37 + 20 = 90). To calculate the component of the force perpendicular to the pole, use trig ratios: cos(33°) = F_x/F so F_x = Fcos(33°) = 104cos(33°) = 87.22 N

So the Torque = (2.2)(87.22) = 192 Nm