Edward C. answered 03/25/15
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Caltech Grad for math tutoring: Algebra through Calculus
Let W (for Win) denote profit in each year and L denote loss. We are given
P(W) = 0.2 in the first year so P(L) = 0.8 in the first year
If there was a profit in the first year then we have
P(WW) = 0.2*0.7 = 0.14 = probability of profit in both years
P(WL) = 0.2*0.3 = 0.06 = probability of profit in year 1 and loss in year 2
P(LW) = 0.8*0.2 = 0.16 = probability of loss in year 1 and profit in year 2
P(LL) = 0.8*0.8 = 0.64 probability of loss in both years
Continuing to the third year we have
P(WWW) = 0.14*0.7 = 0.098
P(WWL) = 0.14*0.3 = 0.042
P(WLW) = 0.06*0.2 = 0.012
P(WLL) = 0.06*0.8 = 0.048
P(LWW) = 0.16*0.7 = 0.112
P(LWL) = 0.16*0.3 = 0.048
P(LLW) = 0.64*0.2 = 0.128
P(LLL) = 0.64*0.8 = 0.512
Of these 8 possibilities, 3 have a profit in exactly 2 of the 3 years, they are
P(WWL) + P(WLW) + P(LWW) = 0.042 + 0.012 + 0.112 = 0.166