Explain??????!!!!!

Question

Write an equation for transformed cosine wave that has the following properties

1)amplitude =3

2)period=pi

3)horizontal shift=none

4) vertical shift=4 units up

Answer 1

We'll need to use the cosine transformation function f(x) = a•cos(bx+c)+d

Amplitude is 3, so a=3

Period is π, so 2π/b = π, which means b=2

Horizontal shift is 0, so -c/b = -c/2 = 0, which means c=0

Vertical shift is 4, so d=4

Final function is f(x) = 3cos(2x)+4

Answer 2

f(x) = cosx=AcosB(x-C) + D where A=1, B=1, C=0, D =0

with A=3, period = pi = 2pi/B, B= 2, C= 0, D = 4

the transformed function is

g(x) = 3cos(2x) + 4