RIshi G. answered 03/05/23
North Carolina State University Grad For Math and Science Tutoring
According to the theory of relativity, the speed of light in a vacuum is constant and is the same for all observers, regardless of their relative motion. This means that the speed of light is always measured to be c = 299,792,458 meters per second, regardless of the motion of the observer or the source of the light.
In this scenario, the spaceship is traveling at half the speed of light, which means its velocity is v = 0.5c. If the spaceship is 10 kilometers ahead of the light, we can calculate the time it would take for the light to reach the spaceship using the equation:
time = distance / speed
The distance between the spaceship and the light is 10 kilometers, or 10,000 meters. The speed of light is c = 299,792,458 meters per second. So the time it would take for the light to reach the spaceship is:
time = 10,000 / 299,792,458 = 0.000033 seconds
Now, let's consider how far the spaceship travels during this time. Since the spaceship is traveling at half the speed of light, its velocity is v = 0.5c. So in 0.000033 seconds, the spaceship would travel:
distance = speed x time = 0.5c x 0.000033 = 4,993 meters
This means that during the time it takes for the light to travel 10 kilometers, the spaceship would have traveled almost 5 kilometers. Therefore, the light would not overtake the spaceship in this scenario.