
Aime F. answered 03/03/23
PhD in Physics (Yale), have taught Methods of Engineering Analysis
The 2 resistors in parallel are equivalent to an R₃ = 1/(1/5 + 1/10) = 10Ω/3.
Equating loop voltages implies
E = (I₁ + I₂)R₀ + I₂(R₂ + R₃) = (I₁ + I₂)R₀ + I₁R₁, which are 2 equations in 2 unknowns, since E = 7V, R₀ = 2Ω, R₁ = 8Ω, R₂ = 6Ω.