Consider the combination of resistors shown in the figure below.

Question

If a voltage of 46.6 V is applied between points a and b, find the current (in A) in each resistor.

12 Ω:

6.0 Ω:

5.0 Ω :

4.0 Ω: 

8.0 Ω:

Answer 1

R = 12·6/18 + 5 + 4·8/12 = 35/3 Om

I(5 Om) = 46.6/(35/3) = 4 A

I(12 Om) = 4·4/12 = 4/3 A = 1.3 A

I(6 Om) = 4·4/6 = 8/3 A = 2.7 A

I(4 Om) = 4·(8/3)/4 = 8/3 A = 2.7 A

I(8 Om) = 4·(8/3)/8 = 4/3 A = 1.3 A