Find the product. Leave the result in trigonometric form. (Let 0 ≤ 𝜃 < 2𝜋.)

Question

[3(cos(𝜋/9) + i sin(𝜋/9))][6(cos(𝜋/18)+ i sin(𝜋/18))]

Answer 1

[3(cos(𝜋/9) + i sin(𝜋/9))][6(cos(𝜋/18)+ i sin(𝜋/18))] = 18[cos(π/9 + π/18) + isin(π/9 + π/18)] = 18(cosπ/6 + isinπ/6)