
Mark M. answered 02/25/23
Mathematics Teacher - NCLB Highly Qualified
216 = ax3
1 = ax0
1 = a
216 = x3
6 = x
y = x3
Kiara B.
asked 02/24/23Mark M. answered 02/25/23
Mathematics Teacher - NCLB Highly Qualified
216 = ax3
1 = ax0
1 = a
216 = x3
6 = x
y = x3
James B. answered 02/24/23
B.S. in Math with 2+ years tutoring experience
We can rephrase this question as finding the exponential function that passes through the points (0, 1) and (3, 216). That is, we move 3 along x and then move 216 along y. Exponential functions are generally given by a^(x) where a is some constant number. Thus we know that, with this unction, a^(0) = 1 and a^(3) = 216. To determine what a is we need to take the cubic root of 216. Working with this number a bit we can see that 216 = 6*6*6 thus the cubic root of 216 = 6. a = 6 giving us the exponential function f(x) = 6^(x) as our result.
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