
William W. answered 02/22/23
Math and science made easy - learn from a retired engineer
We can use this as the half-life equation:
G(t) = G0(1/2)t/h
where G(t) is the amount of the substance left after time "t", G0 is the amount at the start (at time t = 0), "t" is the amount of time that goes by, and "h" is the half-life. Note that "t" and "h" must be in the same units of time.
So, we can say:
2 = 128(1/2)165/h
2/128 = (1/2)165/h
log1/2(2/128) = log1/2(1/2)165/h
6 = 165/h
h = 165/6
h = 27.5 minutes
You start with 128 g, after 27.5 minutes there are 64 g left, after 55 minutes there are 32 g left, after 82.5 minutes there are 16 g left, after 110 minutes there are 8 g left, after 137,5 minutes there are 4 g left, and after 165 minutes, there are 2 g left
Since you now know h = 27.5, you have the equation G(t) = 128(1/2)t/27.5 so you can plug in t = 8:
G(8) = 128(1/2)8/27.5 = 128(1/2)0.29090909 = 128(0,8173868) = 104.63 grams

Mark M.
Were you inspired by 2^7 = 128?02/22/23