precalculus work helo

Question

A town's population has been growing linearly. In 2003 the population was 24,000. The population has been growing by 2200 people each year.

Write an equation for the population, P, x years after 2003.

P =   

Use the formula to find the population in 2009:

Answer 1

I have posted a video of the solution on YouTube: https://youtu.be/t6GwwmuZTbE

Linear equations are defined to have a constant rate of change. In this case, our rate of change, or growth is 2200 people each year.

We will start with a population of 24,000 and then increase the population by adding 2200 people each year, our equation becomes;

P = 24000 + 2200x

where P is the total population, and x is the number of years after 2003.

To find the population in 2009, use the same equation above.

P = 24000 + 2200x

P = 24000 + 2200(6)

P = 37200

(message me if you have any questions, thank you)

Answer 2

P(x)=24+2.2x

P(6)=24+2.2(6)

=37.2 thousand in 2009

= 37,200

Answer 3

To write an equation for the population, we need to determine the slope (rate of change) of the linear growth and the initial value of the population.

We know that the population was 24,000 in 2003, so the initial value is 24,000. We also know that the population has been growing by 2200 people each year, which means that the slope of the linear growth is 2200.

Therefore, the equation for the population, P, x years after 2003 is:

P = 2200x + 24000

To find the population in 2009, we need to substitute x = 6 into the equation:

P = 2200(6) + 24000

P = 13,200 + 24,000

P = 37,200

Therefore, the population in 2009 was 37,200.