Inactive Tutor answered 02/17/23
sqr(1-(cos8T)/2)
half angle formula is
sin(T/2) =+/-sqr((1-cosT)/2)
for 8T
sin8T/2 = +/-sqr((1-cos8T)/2)
sine 4Theta = the simplest way to write the expression
sin4T is the answer
Armaan S.
asked 02/16/23Simplify the expression by using a Double-Angle Formula or a Half-Angle Formula.
square root 1-cos(8theta)/2
Inactive Tutor answered 02/17/23
sqr(1-(cos8T)/2)
half angle formula is
sin(T/2) =+/-sqr((1-cosT)/2)
for 8T
sin8T/2 = +/-sqr((1-cos8T)/2)
sine 4Theta = the simplest way to write the expression
sin4T is the answer
Inactive Tutor answered 02/17/23
Because of the square root and that under the radical, we have a 1 - cosine, we will be using the identity:
sin(theta/2)=sqrt( (1 - cosine (theta)) / 2)
Now all we have to do is plug in the 8*theta where appropriate on the left side of the equation and simplify:
sin ((8*theta) / 2) = sin (4*theta)
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