Raymond B. answered 05/11/24
Math, microeconomics or criminal justice
cos^6(x)
=(cos^2(x)(cos^2x)(cos^2x)
=cosxcosxcosxcosxcosxcosx is a product of 6 cosines of x in linear form
or
= (cos2x +1)/2)^3= 0.125(cos2x+1)^3
=(1/8)(cos2x+1)(cos2x+1)(cos2x+1) which is a product of 3 cosines of 2x, each factor in linear form
or with I=Integral
I(cos^6(x))dx = (cos(x)^5(sinx))/6 +5x/16 +5sin(2x)/32 + (5cos(x)^3(sinx))/24 + C
using consine reduction formula
Icos^6(x)dx= (cos^5)(sinx)/6 + 5(.25cos^3(x)sinx+.75I.5cosxsinx + C