Daniel B. answered 02/17/23
A retired computer professional to teach math, physics
Let
m1 = 3g be the mass of marble 1,
m2 = 2g be the mass of marble 2,
v1 = 6 m/s be the initial speed of marble 1,
v2 = 0 m/s be the initial speed of marble 2,
w1 = 4 m/s be the final speed of marble 1,
w2 = 4 m/s be the final speed of marble 2.
The final momentum is directed to the right and has magnitude
m1w1 + m2w2 = 3×4 + 2×4 = 20 gm/s
For conservation of momentum the initial momentum must also be to the right.
So one improvement in the report would be to say that the initial velocity is to the right.
The magnitude of the initial momentum is
m1v1 + m2v2 = 3×6 + 2×0 = 18 gm/s
There are a many changes to the report that would make the two momenta equal.
One thing we should not change is w1 = w2.
That indicates that the marbles stick together, which implies inelastic collision,
which then does require conservation of mechanical energy.
Here are some examples of a change to the report that would make the two momenta equal:
1) v2 = 1 m/s
2) w1 = w2 = 18/5 m/s
3) v1 = 20/3 m/s
4) m2 = 1.5 g
And there are many other possibilities.