Aime F. answered 02/17/23
PhD in Physics (Yale), have taught Methods of Engineering Analysis
For the box, Newton's 2nd Law along the vertical direction reads N – m₁g = m₁a.
KURT R.
asked 02/16/23A box (m1 = 1.0 kg) is in an elevator which is accelerating upward at 3.00 m/s^2. The elevator has a mass of m 2 = 2000 kg. Find the normal force on the box from the elevator.
a) Draw a Free Body Diagram (FBD) of m1 or m2. Include coordinate axes!
b) Split the forces on m 1 or m 2 into y components.
c) Use Newton’s Laws to determine the normal force of the box .
Aime F. answered 02/17/23
PhD in Physics (Yale), have taught Methods of Engineering Analysis
For the box, Newton's 2nd Law along the vertical direction reads N – m₁g = m₁a.
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