The secant of an angle is sec(x)=13/5 what is its tangent?

Question

The secant of an angle is sec(x)=13/5 what is its tangent?

Answer 1

secx = 13/5 =2.6

cosx = 5/13

x is in quadrant I or IV= about 67.38 or -67.38

tan67.38 = 2.4

tan-67.38 = -2.4

or

cosx = adjacent side over hypotenuse = a/h

a =5, h=13

opposite side squared = o^2 = h^2 -a^2 = 13^2 -5^2 = 169-25 = 144

opposite side = o = +/-sqr144 = 12 or -12

tangent x = tanx = o/a = 12/5 or -12/5

tanx = 2.4 or -2.4