
Yefim S. answered 02/14/23
Math Tutor with Experience
14/6 = (8t + l)/l; 7l = 3l + 24t; l = 6t; dl/dt = 6 ft/s.
So, length of shadow increasing with constant speed
Maureen J.
asked 02/14/23A street light is at the top of a 14 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 8 ft/sec along a straight path. How fast is the length of her shadow increasing when she is 45 ft from the base of the pole?
Note: How fast the length of her shadow is changing IS NOT the same as how fast the tip of her shadow is moving away from the street light.
Yefim S. answered 02/14/23
Math Tutor with Experience
14/6 = (8t + l)/l; 7l = 3l + 24t; l = 6t; dl/dt = 6 ft/s.
So, length of shadow increasing with constant speed
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