Physics Question

Question

The acceleration of a particle moving only on a horizontal xy plane is given by ?→=5??ˆ+6??ˆa→=5ti^+6tj^, where ?→a→ is in meters per second-squared and t is in seconds. At t = 0, the position vector ?→=(26.0m)?ˆ+(36.0m)?ˆr→=(26.0m)i^+(36.0m)j^ locates the paticle, which then has the velocity vector ?→=(6.70m/s)?ˆ+(1.90m/s)?ˆv→=(6.70m/s)i^+(1.90m/s)j^. At t = 4.60 s, what are (a) its position vector in unit-vector notation and (b)the angle between its direction of travel and the positive direction of the x axis?

Answer 1