Mohammed A. answered 02/09/23
A Physics & Math Grad getting young minds enjoy math and science
The initial acceleration (a1) = 100g
The final acceleration (a2) = 7*(100g) = 700g
We know, a = rω2
So, ω = √(a/r)
Since r here is constant,
The final and initial rotation rates are related as follows-
ω1 / ω2 = √(a1 / a2)
So, ω2 = (ω1) / (√(a1 / a2))
= (ω1) / (√(100g / 700g)
= 2.646 * ω1
Therefore, the rotational speed has to increase by a factor of 2.646 times the initial rotational speed.