In a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 12.0m in diameter. At what acceleration (in SI units) does the pilot blackout?

Question

In a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 12.0m in diameter.

At what acceleration (in SI units) does the pilot blackout?

Express this acceleration in terms of a multiple of g?



If you want to decrease the acceleration by 13% without changing the diameter of the circle, by what percent must you change the time for the pilot to make one circle?

Answer 1

There is not enough information provided for the blackout question.

For the next question, the time to make one circle is the period T = 2π/ω, while the acceleration is a = ω²r = 4π²r/T². Therefore, approximately Δa ≈ –8π²rΔT/T³ = –2aΔT/T and ΔT/T ≈ –Δa/2a = 6.5% i.e., increased period.