A 2.0 kg ball strikes a wall with a velocity of 8.6 m/s to the left. The ball bounces off with a velocity of 7.4 m/s to the right.

Question

If the ball is in contact with the wall for 0.22 s, what is the constant force exerted on the ball by the wall?

Answer 1

F= m(v_f - v_i)/t = 2kg(8.6m/s + 7.4m/s)/0.22s = 145.45 N