Simplify each and state the excluded values

Question

p^(2)-25/(p-5)

Answer 1

     (p² - 25) / (p - 5)

Notice that the numerator is a difference of squares and can be factored as follows:

     p² - 25 = p² -5² = (p - 5)(p + 5)

Therefore,

     (p² - 25) / (p - 5) = ((p -5)(p + 5)) / (p - 5)

Since  p - 5  is in both the numerator and the denominator, they cancel out (i.e., they are the excluded values):

     ((p - 5)(p + 5)) / (p - 5) = (p + 5)

Thus,

     (p² - 25) / (p - 5) = p + 5