
Yefim S. answered 02/02/23
Tutor
5
(20)
Math Tutor with Experience
Total number of different gifts are possible: N = C(7, 6)·C(6, 3) = 7·20 = 140
Brysen R.
asked 02/02/23How many different gift packages are possible?
Yefim S. answered 02/02/23
Math Tutor with Experience
Total number of different gifts are possible: N = C(7, 6)·C(6, 3) = 7·20 = 140
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