Final Temperature

Question

A 1.9 g potato chip containing 3 cal is completely burned in a kilo meter that contain 60 mL of water at an initial temperature of 50° Celsius, if all the energy of the potato chip is transferred to the water what is the final temperature of the water?

Answer 1

To calculate the final temperature of the water, we can use the principle of conservation of energy, which states that the energy released by the burning potato chip is equal to the energy absorbed by the water. We can use the specific heat formula to calculate the change in temperature of the water.

First, let's calculate the energy released by the burning potato chip:

Energy = 3 cal

Next, let's calculate the heat absorbed by the water:

Heat absorbed = Energy released = 3 cal

Now, we need to calculate the change in temperature of the water. We can use the specific heat formula:

Q = mcΔT

Where:

Q = Heat absorbed

m = Mass of water

c = Specific heat of water

ΔT = Change in temperature

The mass of water is given as 60 mL, but we need to convert it to grams since the specific heat is typically given in terms of grams.

1 mL of water has a mass of approximately 1 gram, so:

Mass of water (m) = 60 grams

The specific heat of water (c) is approximately 1 calorie/gram°C.

Now we can rearrange the formula and solve for ΔT:

ΔT = Q / (mc)

ΔT = (3 cal) / (60 g * 1 cal/g°C)

ΔT = 0.05°C

Therefore, the final temperature of the water will increase by approximately 0.05°C. Since the initial temperature was 50°C, the final temperature will be approximately 50.05°C.