Joshua S. answered 9d
FAA Aerospace Engineer and CPP Masters Student
Exploring the Cost of Transport
Step 1: Minimum cost of transport
The bird’s oxygen consumption is lowest at 10 m/s where VO₂ = 5.1 mL O₂ / kg·s.
Convert this to a whole-animal rate:
Vdot_O2,bird = 5.1 mL O₂ / kg·s × 0.0805 kg = 0.411 mL O₂ / s
To express as cost of transport (mL O₂ per m body mass):
COT = 0.411(0.0805)(10) = 0.51 mL O₂·g⁻¹·km⁻¹
So the minimum cost of transport ≈ 0.51 mL O₂ · g⁻¹ · km⁻¹, or about 41 mL O₂ per km for the entire 80.5 g bird.
Step 2: Range using 3 g of fat
Energy from 3 g fat:
3 g × 39.3 kJ/g = 118 kJ
Each g fat → 2.0 L O₂ consumed → 3 g → 6 L O₂ available.
O₂ cost per km ≈ 0.041 L, so
6L / 0.041 L km⁻¹ ≈ 146 km
That’s roughly 90 miles of flight on 3 g of fat.
Step 3: Heat production
Muscle efficiency = 25%, so 75% becomes heat:
118 kJ × 0.75 = 88.5 kJ of heat
If the flight lasts 146 km / 10 m s⁻¹ ≈ 14 600 s (≈ 244 min):
88.5 kJ / 244 min ≈ 363 J min⁻¹ heat
Step 4: Respiratory Exchange Ratio (RER)
For triglyceride C₅₁H₁₄₀O₆:
C₅₁H₁₄₀O₆ + 72.5 O₂ → 51 CO₂ + 70 H₂O
RER = 51 / 72.5 ≈ 0.70, typical of pure fat metabolism.
Step 5: Total CO₂ produced
6 L O₂ × 0.70 = 4.2 L CO₂ produced over the full flight.
Step 6: Compare to a walker/runner (chipmunk-sized)
Weight-specific COT (walkers/runners):
8.46M^(−0.40) = 8.46(80.5)^(−0.40) ≈ 1.65mL O₂·g⁻¹·km⁻¹
Bird’s COT ≈ 0.51 mL O₂·g⁻¹·km⁻¹.
Factor = 1.65/0.51 ≈ 3.2
So walking/running costs about 3× more energy than flying for the same-mass animal.
Summary
- Minimum COT: 0.51 mL O₂ · g⁻¹ · km⁻¹ (≈ 41 mL O₂/km whole-animal)
- Range on 3 g fat: ~90 miles
- Heat output: ≈ 360 J min⁻¹
- RER: 0.70
- CO₂ produced: 4.2 L
- Walker vs Flier cost: ≈ 3× higher for walker