A 1.30 kg skateboard is coasting along the pavement at a speed of 8.0 m/s when a 0.950 kg cat drops from a tree vertically downward onto the skateboard.

Question

What is the speed of the skateboard-cat combination.

Answer 1

By Law of conservation of momentum: 1.3·8 = (1.3 + 0.95)v; v = 10.4/2.25 m/s = 4.622 m/s