Yefim S. answered 01/26/23
Math Tutor with Experience
v(t) = dh/dt = - 32t + 16 = 0; t = 0.5 s
hmax = h(05) = - 4 + 8 + 480 = 484 feet
h(t) = - 16t2 + 16t + 480 = 0; t2 - t - 30 = 0; t = 6 s
Micah M.
asked 01/26/23t is time in seconds, h is height in feet. 17) How long did it take for Kasey to reach max height? 18) What was the highest point Kasey reached? 19) Kasey hit the water after how many seconds?
Yefim S. answered 01/26/23
Math Tutor with Experience
v(t) = dh/dt = - 32t + 16 = 0; t = 0.5 s
hmax = h(05) = - 4 + 8 + 480 = 484 feet
h(t) = - 16t2 + 16t + 480 = 0; t2 - t - 30 = 0; t = 6 s
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