indentation error

Question

sentence = input("Enter a word:")

vowel_count = 0

for i in sentence:

if(i == "a" or i == "e" or i == "i" or i == "o" or i == "u"):

vowel_count = vowel_count + 1

print("Total vowel count :", vowel_count)

why am i getting in indentation error.

Answer 1

Use Shift-TAB and TAB in vsCode or in Pycharm to move text left and right for indentation errors

x = x + 1 and many other examples above is not Pythonic,

Please see example below

def vowels(sentence):

nvowels = 0

vowels = 'aeiou'

words = sentence.split()

for word in words:

for letter in word:

letter = letter.lower()

if letter in vowels or (letter == word[-1] and letter == 'y'):

nvowels += 1

return nvowels

def test_vowels_in_sentence(sentence):

print(f'{sentence:50} ..... has {vowels(sentence)} vowels')

def test_vowels():

print('\n..................BEGINNING test_vowels()...............')

test_vowels_in_sentence('supEr')

test_vowels_in_sentence('super bOwl')

test_vowels_in_sentence('supEr bOwl in pAsAdena')

test_vowels_in_sentence('A rose by any other name would smell as sweet')

test_vowels_in_sentence('Help me Obiwan you are my only hopE')

test_vowels_in_sentence('I have been here before but always hit the floor')

print('..................ending test_vowels()..................\n')

def main():

test_vowels()

if __name__ == '__main__':

main()

#=========================================================

# OUTPUT

#=========================================================

# ..................BEGINNING test_vowels()...............

# supEr ..... has 2 vowels

# super bOwl ..... has 3 vowels

# supEr bOwl in pAsAdena ..... has 8 vowels

# A rose by any other name would smell as sweet ..... has 16 vowels

# Help me Obiwan you are my only hopE ..... has 14 vowels

# I have been here before but always hit the floor ..... has 17 vowels

# ..................ending test_vowels()..................

Answer 2

Whenever you write an if statement, python needs to know what code to run if the statement is True. Python uses indentation for this reason. The vowel_count variable addition should only run when the if statement is True, so the vowel_count = vowel_count + 1 part should be directly below the if statement and indented one time.

Just as an extra, when you want to increment a variable by 1, which is what you did to vowel_count, you can use the += operator. vowel_count += 1 works just as well.

sentence = input("Enter a word:")

vowel_count = 0

for i in sentence:

if(i == "a" or i == "e" or i == "i" or i == "o" or i == "u"):

vowel_count = vowel_count + 1

print("Total vowel count :", vowel_count)