Wail S. answered 01/16/23
Experienced tutor in physics, chemistry, and biochemistry
Hi Omar,
We can analyze this inelastic collision by applying the conservation of linear momentum (ΔP = 0).
Conceptual/extra details: Remember that this idea of momentum conservation comes from F = ma in the scenario where the sum of all forces is equal to zero. This is true for our scenario here because when cars collide on a flat frictionless surface they apply equal and opposite forces on each other. However, If this collision were to instead take place on a slanted surface for example, the net force would NOT be zero because gravity would have an influence (gravity not be balanced by the normal force in this case) and momentum would NOT be conserved.
Part A, B
ΔP = Pf - Pi = 0
What is Pinitial, the initial momentum of the system? Let's take the direction of block 1s motion to be the positive direction.
Pi = m1v1 + m2v2 = m1v1 + 0 (the second block's initial velocity is zero)
What is Pfinal? Remember that the blocks are sticking together, and thus acting as one combined mass at the end of the scenario. Together, they move with some final velocity vf
Pf = (m1+m2)vf
Apply these equations into equation 1
ΔP = Pf - Pi = ((m1+m2)vf) - (m1v1) = 0
This gives
(m1+m2)vf = (m1v1)
Then just solve this for vf
Part C
ΔKE = KEf - KEi
Initial KE is:
KEi = (1/2) m1v12 + (1/2) m2v22 = (1/2) m1v12 + 0 (the second block's initial velocity is zero)
final KE is:
KEf = (1/2) (m1+m2)vf2
Then just plug this into the ΔKE = KEf - KEi equation. You will notice that the kinetic energy is actually NOT conserved for this collision. This isn't because energy is beying destroyed. Some of the kinetic energy from the initial state is just simply lost as the blocks collide with each other and interact as they stick (this energy results in the sound of the collision, the heating of the colliding objects, and their deformation).