Hi Everett,
I don't know you, so I have to guess what part(s) of this question have got you stumped.
First, the 6 o'clock position refers to the lowest part of the wheel.
Second, as the wheel goes around and around the heights of the riders repeat in a periodic way and a graph will look like a sine or cosine wave, yes?
Since the riders board the Ferris wheel at the bottom, when t = 0, a cosine function would be better than a sine function, because they start at 0. In fact, since this is the LOWEST position, an inverted cosine function would perfect. Therefore, the amplitude coefficient will be negative.
Do you agree that the amplitude of the function would be 10, the radius of the Ferris wheel?
Do you see that the center of the Ferris wheel is 12 meters off the ground?
And that this height represents a vertical shift.
So far, we can see that h(t) = -10 Cos (Bt) +12, yes.
But how to we determine B?
Your teacher may have given you a formula to memorize, but I'm going to show a way to proceed even if you can't remember the formula.
We know that one complete rotation occurs when Bt = 2π.
We also know that this occurs when t = 10.
Substitute 10 for t and solve for B.
B = (2π)/10 and this reduces to π/5.
Our final function is h(t) = -10 Cos (πt/5) + 12.
I hope this helps.
Doug C.
I was in the process of answering this question, but Michael's answer is perfect, so I will just add a link to this Desmos graph that depicts the situation. desmos.com/calculator/0iqsoivggb Drag the purple point along the cosine graph to see the little blue x running along the Ferris wheel and having the same height as the point on the cosine graph. Also make note of the fact that you can convert to a sine function by adding a phase shift 2.5 to the left.12/19/22