The original moles of oxygen can be obtained from the ideal gas law n = PV/RT with P = 4.013x105 (Pguage + Patm = Pabs) T = 310 K and R = 8.314 m3 •Pa/mole•K
m = (32 g/mole)n
The final moles of gas are obtained by the same equation, but with P = 2.813x105, T = 295 K
The amount of O2 leaked is the difference between the two masses.
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