Josias D.
asked 12/16/22Find the missing values assuming continuously compounded interest. (Round your answers to two decimal places.)
| Initial | InvestmentAnnual | % RateTime to | DoubleAmount After | 10 Years |
| $1500 | ||||
| 71 | ||||
| 2 | % | yr | $ |
2 Answers By Expert Tutors
the underlying formula that you want to use here for continuous compounding is
A = P*e^(rt)
for this scenario that means taking
A = 1500 * e^(0.07*10)
A = 3020.63
meaning that the accumulated amount in the account after 10 years is $3,020.63
then for the time to double you can take
t = ln(2) / r
t = ln(2) / 0.07 = 9.90 years
Raymond B. answered 02/18/23
Math, microeconomics or criminal justice
Use the formula
A = Pe^rt
where
P = Iniitial Investment
r= annual rate of interest
t = number of years
e = about 2.718281828
A= ending Amount continuously compounded at r interest rate for t years, with P=initial amount
plug in the values, use a calculator. Multiply P by e^rt
e^rt is the limit of (1+r/n)^nt as n approaches infinity
n= number of compounding periods per year
r= annual interest rate, t = years
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Mark M.
Repost without the table format. Three of the same type. Do you have a specific question?12/16/22