PRECALCULUS for economics

Question

Dylan invests $15,000 in three different stocks. One stock is very risky and after 1 yr loses 8%. The second stock returns 3.2%, and a third stock returns 5.8%. At the end of 1 yr, the total return is $274. If he invested $2000 more in the second stock than in the third stock, determine the amount he invested in each stock.

Answer 1

Let x = amt of the first investment

Let y = amt of the second investment

Let z = amt of the third investment

From the total amount invested, we get this equation

x+y+z=15000

From the interest earned we get the following equation

-0.08x+0.032y+0.058z=274

The third equation gives us the following: second = 2000+third

y=2000+z

I can solve this system any method I like, I used the rref feature on the calculator

Let x = amt of the first investment = $3000

Let y = amt of the second investment = $7000

Let z = amt of the third investment = $5000

Answer 2

t represents the amount in the third stock

t + 2000 represents the amount in the second stock

15000 - (t + 2000) represents the am 2000oung in the first stock

-0.08(13000 - t) + 0.032(t + 2000) + 0.058t = 274

Can you solve for t and answer?