What is the impulse on a 45,000 kg airplane when it changes its velocity from 242 m/s to 258 m/s?

Question

720,000 kg·m/s

2,800 kg·m/s

16 kg·m/s

440,000 kg·m/s

Answer 1

FΔt or impulse = Δmv = mΔv= m(v_f-v_i)

All the units are MKS, so you will obtain kgm/s or N-s.

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