If tant=1/3 , what is tan(t−π)?

Answer 1

tan(t - π) = [tant - tanπ] / [1 +(tant)(tanπ)] = [1/3 - 0] / [1 +(1/3)(0)] = 1/3

Note: tan t is periodic with period π. So, the value of tan t is always the same as the value of tan(t - π).

Answer 2

tant = 1/3

tan(t-pi) = tan(t+pi) = tant = 1/3

t = tan^-1(1/3) = about 18.44 degrees

tan18.44 = 1/3

tan198/44 = 1/3

tan(18.44-180) = tan-161.56= 1/3

add or subtract 180 degrees or pi, or any integer multiple of 180 or pi and the tangent of the angle remains the same