Given that: cos(0)=-4/7 and 0[0,pi]; find sin(0), tan(0), cot(0), sec(0), and csc(0)

Question

0 is delta I don't know how to put the symbol in

E=∈

Answer 1

cosT =-4/7 = adjacent side over hypotenuse

secT = -7/4 = hypotenuse over adjacent side

sinT = sqr(49-16)/7 = (sqr33)/7 = opposite side over hypotenuse

cscT = 7/sqr33 = 7(sqr33)/33 = hypotenuse over opposite side

tanT = sinT/cosT = opposite side over adjacent side = -(sqr33)/4

cotT = 1/tanT = -4/sqr33 = -4(sqr33)/33

hypotenuse squared = opposite side squared + adjacent side squared

h^2 = o^2 +a^2

7^2 = (sqr33)^2 +16 = 49

Let T = Theta, where 0<T<pi

since CosT <0,

Theta is in quadrant II and pi/2<T<pi

T is about 180-55/15 = 124.85 degrees = about 2.18 radians

= about 124.85pi/180 = about 0.7pi radians