What is y-12y+4x+4=0 as a parabola

Yefim S. answered • 12/07/22

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y² - 12y + 4x + 4 = 0; (y² + 12y + 36) + 4x + 4 - 36 = 0; (y + 6)² = - 4(x - 8).

This is horizontal parabola with vertex at point (8, - 6), p = - 1. Focus at point (7, - 6) and directrix x = 9

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