What is x^2-4x+12y-8=0 as a parabola

Question

Write as a parabola

Answer 1

-12y = x² - 4x - 8

-12y = x³ - 4x + 4 - 12

-12y = (x - 2)² - 12

y = (-1/12)(x - 2)² - 1

The parabola opens downward with vertex (maximum point) (2, -1).

Answer 2

Hi Surah K

Solve for y below is a start

-12y = x² - 4x - 8

Can you continue?