Joseph D. answered 12/03/22
Hi Charlie P.,
Using y = y0 + vy*t + a*t2/2 for the vertical fall (positive y-direction up), and x = vx*t for the horizontal distance. vx = 39 m/s; y0 = 1.5 m; vy = 0; a = 9.8 m/s2, we get:
0 = 1.5 - 4.9*t2
t2 = 1.5/4.9
t = 0.55328 s
x = vx*t = 39*0.55328 = 21.6 m
I hope this helps, Joe.