Mark M. answered 12/03/22
Tutor
4.9
(953)
Retired math prof. Very extensive Precalculus tutoring experience.
cosy + 1 = 2sin2y
cosy + 1 = 2(1 - cos2y)
2cos2y + cosy - 1 = 0
(2cosy - 1)(cosy + 1) = 0
cosy = 1/2 or cosy = -1
cosy = 1/2 when y = 60ˆ or 300°
cosy = -1 when y = 180°
Solution set: {60°, 180°, 300°}
Gisele G.
Thank you!12/03/22