Solve for x. log2x+log(2x-1)=log3x

Question

Answer 1

log(2x) + log(2x-1) = log(3x)

log[(2x)(2x-1)] = log(3x)

4x² - 2x = 3x

4x² - 5x = 0

x(4x - 5) = 0

x = 0 or x = 5/4

Since log(0) is undefined, we can eliminate 0 from consideration.

So, the only solution is 5/4.