Inactive Tutor answered 11/28/22
sin(A-B)=sin(A)cos(B)-sin(B)cos(A)
A=sin-1(3/5),,,,,,A=cos-1(4//5),,,,,,,B=cos-1(4/5),,,,,,B=sin-1(3/5)
sin(A-B)=12/25-12/25=0
sin(2A)=2sin(A)cos(A)
A=sin-1((√3)/2),,,,,A=cos-1(1/2)
sin(2A)=2*((√3)/2)*(1/2)
Katelyn A.
asked 11/28/22Find exact value of each expression:
a) sin(sin^-1 (3/5) - cos^-1 (-4/5)
b) sin(2 sin^-1 (sqrt(3) /2) )
Inactive Tutor answered 11/28/22
sin(A-B)=sin(A)cos(B)-sin(B)cos(A)
A=sin-1(3/5),,,,,,A=cos-1(4//5),,,,,,,B=cos-1(4/5),,,,,,B=sin-1(3/5)
sin(A-B)=12/25-12/25=0
sin(2A)=2sin(A)cos(A)
A=sin-1((√3)/2),,,,,A=cos-1(1/2)
sin(2A)=2*((√3)/2)*(1/2)
Inactive Tutor answered 11/28/22
Both are based on basic triangles. Draw and label.
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