
Dayv O. answered 11/28/22
Attentive Reliable Knowledgeable Math Tutor
sin(A-B)=sin(A)cos(B)-sin(B)cos(A)
A=sin-1(3/5),,,,,,A=cos-1(4//5),,,,,,,B=cos-1(4/5),,,,,,B=sin-1(3/5)
sin(A-B)=12/25-12/25=0
sin(2A)=2sin(A)cos(A)
A=sin-1((√3)/2),,,,,A=cos-1(1/2)
sin(2A)=2*((√3)/2)*(1/2)